Rudy Gobert named 2024 NBA Defensive Player of the Year

Minnesota Timberwolves center Rudy Gobert won the 2024 NBA Defensive Player of the Year award on Tuesday, matching a league record by taking the honor for the fourth time.

The 31-year-old Frenchman previously captured the award in 2018, 2019 and 2021 while with the Utah Jazz and this season was a key player on a T-Wolves squad that was the NBA's top-ranked defensive club.

Gobert matched the all-time record four Defensive Player of the Year awards won by Detroit's Ben Wallace (2002, 2003, 2005, 2006) and Dikembe Mutombo in 1995, 1997, 1998 and 2001 with Denver, Atlanta and Philadelphia.

The 7-foot-1 (2.16m) star missed Minnesota's playoff victory at Denver on Monday so he could be with girlfriend Julia Bonilla, who gave birth to their son on Monday.

"Romeo is the name and he's doing great," Gobert told US NBA telecaster TNT. "A lot of blessings. Just really grateful."

Gobert's fourth top defender award in seven years saw him with 72 first-place votes in a media panel vote with fellow Frenchman Victor Wembanyama, the 20-year-old San Antonio Spurs prodigy named Monday as the NBA Rookie of the Year, second with 19 first-place votes and Miami's Bam Adebayo third with three.

Gobert averaged 14.0 points, 12.9 rebounds, 2.1 blocked shots and 1.3 assists a game this season for the Timberwolves.

"Rudy has driven the defensive culture here," Timberwolves coach Chris Finch said. "It's a testament to his impact, his presence and what he has infused into the team of how important defense is and how great it can be when we play it."

Gobert, traded to Minnesota from Utah in July 2022, became the first T-Wolves player to capture the top defender award.

The Timberwolves swept Phoenix in the first round of the NBA playoffs and own a 2-0 lead over defending champion Denver after two road triumphs.

Gobert, 31, helped France take Olympic silver in Tokyo and will be a key player for his homeland at the Paris Olympics.