Woman who gave birth to septuplets loses six

All seven babies were born prematurely, faced several complications

Ihsan Dawar October 26, 2021


A woman who gave birth to septuplets after going through surgery at Jinnah International Hospital Abbottabad (JIHA) has lost six of her newborn babies.

According to doctors at the pediatric nursery ward of Ayub Teaching hospital, five of the seven newborns passed away at a private hospital, and the remaining two were shifted to their hospital as their condition remained unsatisfactory.

In charge of the pediatric ward at the hospital, Dr Ijaz Hisain told The Express Tribune that the sixth baby passed away on Tuesday due to premature birth-related complications. The seventh baby is currently under treatment.

All seven babies were born prematurely, weighed around 1 kilogram, and faced several complications, Dr Ijaz stated.

Read Punjab witnesses decline in number of women medics

Last week, one of the baby boys passed away at JIHA.

The hospital’s Administrator Raja Mahboob Janjua told The Express Tribune that one baby boy, who was in an incubator since he was born, died after just two days.

Three other baby girls and three baby boys, along with their mother, were reported to be in good health at the time.

JIHA’s gynecologist, Dr Hina Fiaz, who performed the complicated surgery on the woman said, “The woman was using a certain contraceptive which led to the maturity of more eggs and resulted in more pregnancies at once”.

She performed the complicated operation after which a woman gave birth to septuplets at JIHA. “The ultrasound and other reports had suggested the mother was pregnant with five children and she was in her third trimester,” she said.


Replying to X

Comments are moderated and generally will be posted if they are on-topic and not abusive.

For more information, please see our Comments FAQ


Most Read