Nabil Gabol wins NA-246 from Karachi

Gabol receives 108,000 votes while his opponent manages to get only 7,000.


Web Desk May 11, 2013
Nabil Gabol. PHOTO: ONLINE/ FILE

Muttahida Qaumi Movement candidate Nabil Gabol wins the NA-246 from Karachi against Jamaat-e-Islaami candidate Rashid Naseem, according to unofficial results.

Gabol received 108,000 votes, while Naseem managed to get only 7,000.

In the 2008 elections, the constituency seat went to MQM candidate Sufyan Yousaf who won against Pakistan Peoples Party candidate Sohail Ansari.

COMMENTS (13)

Chandni | 10 years ago | Reply

@Kashif

Correcting your Math.

Average Votes Cast in 10 Hours in a booth = 935

Average Votes Cast in 1 Hours in a booth = 935/10=93.5 Average Vote CAst in a Minute = 93.5/60= 1.55

So it needed 45 seconds to cast a vote .

Kashif | 10 years ago | Reply

NA-246 Karachi 1. Nabil Gabool (MQM): 180 000 2. Naseem (Jamat-i-Islami): 7000 Total votes cast in 10 hours = 187,000 Total Booths in NA 246= 200 Average vote casted in 1 booth during 10 hours= 935 Average Votes cast in 1 hour or 60 minutes at 1 booth--935/60=15.6

Please Note this ratio implies on 200+ booths. so it is quite normal to cast 15 or 16 votes in 1 hour. Please do not give calculations until it is not confirmed.

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